Calculus
posted by Anonymous
Find the first and second derivative for the function
g(t)=t^2(3t+1)^4

Steve
g' = (2t)(3t+1)^4 + (t^2)(4)(3t+1)^3 (3)
= 2t(9t+1)(3t+1)^3
g'' = 2(135t^2 + 30t + 1)(3t+1)^2
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