1.
Which set represents a Pythagorean triple? (1 point)
27, 38, 42
33, 44, 55
35, 38, 42
68, 72, 81
2.
Which number completes the Pythagorean triple: 12, 16, ____? (1 point)
18
20
22
24
3.
A base ball diamond is square. The distance from home plate to first base is 90 feet. In feet, what is the distance from home plate to second base? (1 point)
127
81
19
13
4.
A town clock has a minute hand that is 1.5 meters long and an hour hand that is 1.2 meters long. What is the approximate distance in meters between the ends of the hands at 9 o’clock? (1 point)
2.3
1.9
0.9
0.3
5.
A television set is 36 inches wide and has a diagonal length of 42 inches. To the nearest inch, how tall is the set? (1 point)
9
13
22
55
Are my answers correct?
1. 33, 44, 55
2. 20
3. 19
4. 1.9
5. 55
I am confused about 3....can you explain how do do it?
1. 33, 44, 55
2. 20
3. 127
4. 1.9
5. 22
These are the right answers i got a 100%
3 and 5 are wrong.
3. The distance between home plate and second base is the hypotenuse. The two sides of this right angle triangle are 90 feet and 90 feet.
To find the distance from home plate to second base on a baseball diamond, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, the distance from home plate to first base is given as 90 feet, and we want to find the distance from home plate to second base. To visualize this, imagine a right triangle formed by the home plate, first base, and second base.
Since the baseball diamond is square, we know that the distance from home plate to first base is the same as the distance from first base to second base.
Let's label the distance from home plate to first base as "x" and the distance from home plate to second base as "y". We can write the equation:
x^2 + x^2 = y^2
Simplifying this equation, we get:
2x^2 = y^2
Taking the square root of both sides, we have:
sqrt(2x^2) = sqrt(y^2)
sqrt(2)x = y
We are given that x = 90 feet, so substituting this value in the equation, we have:
sqrt(2) * 90 = y
Calculating this, we get:
y ≈ 127 feet
Therefore, the correct answer for the distance from home plate to second base is 127 feet.
Thankyou so much @kendall
got 100%
:)