Algebra

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Can you please help me understand this? Thanks

Find the value of y so that the passing line through the two points has the given slope.

1. (2,y) (3,3) ;m=2

  • Algebra -

    Two-point form of linear equation :

    y - y1 = ( y2 - y1 ) * ( x - x1 ) / ( x2 - x1 )

    Add y1 to both sides

    y - y1 + y1 = ( y2 - y1 ) * ( x - x1 ) / ( x2 - x1 ) + y1

    y = ( y2 - y1 ) * ( x - x1 ) / ( x2 - x1 ) + y1

    Alope-intercept form of linear equation :

    y = m x + b

    In this case :

    x1 = 2

    y1 = y

    x2 = 3

    y2 = 3

    m = ( y2 - y1 ) / ( x2 - x1 ) = 2

    ( 3 - y ) / ( 3 - 2 ) = 2

    ( 3 - y ) / 1 = 2

    3 - y = 2 Subtract 2 to both sides

    3 - y - 2 = 2 - 2

    1 - y = 0 Add y to both sides

    1 - y + y = 0 + y

    1 = y

    y = 1

  • Algebra -

    just find the slope for the two points, set it equal to 2

    (y-3)/(2-3) = 2 --- (y-3)/-1 = 2
    y-3 = -2
    y = 1

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