CHEM LAB Help
posted by Den .
Weight of the mustard package Sample: 3.02 (g)
Weight of the mustard package Solution: 33.3 (g)
Trial #1 Trial #2 Trial #3
Weight of Mustard Package Solution Delivered (g) : 1.09 .948 .909
Weight of NaOH Solution Delivered (g) : .354 .304 .269
Concentration of NaOH : 7.48e-3 (g of NaOH/g of solution)
Calculate the weight percent of Mustard in your originally prepared solution.
Forget it i got the answer
What are you titrating?
mustard solution, how would i calculate the mass of naOH used?
mols NaOH used is M x L = ?mols NaOH used.
g NaOH used = mols x molar mass NaOH.
After getting this, in order to convert the three masses into moles, what do I divide each mass by
The molar mass of what ever it is you are converting to mols. Which harks back to my original question of what are you titrating. The NaOH surely is titrating an acid; therefore, I expect you want grams of the acid. So mols of NaOH = M x L. Most of acid probably = mols NaOH (I assume a 1:1 reaction).
mol acid x molar mass acid = grams.
grams x the dilution factor converts g in the original sample to grams of the titrated sample.
%acid = (g acid/mass sample)*100 = ?
mols = grams/molar mass.