posted by junior .
one side of an equilateral triangle is 7 dm shorter than one side of square.the sum of the perimeter of the two figure is 49 dm . find the perimeter of each figure.
x = length of one side of a square
x - 7 = length of one side of an equilateral triangle
4x + 3(x - 7) = 49
Solving for x:
4x + 3x - 21 = 49
7x - 21 = 49
7x = 70
x = 10
Now you should be able to determine the perimeter of each figure.
I hope this helps.