PHYSICS!!!!!!!!!!!!!!!!
posted by NEED HELP ASAP!!!!!!!!!!! .
the height from where the water bomb will be released on the overpass is 4.5 m and the target student is 170 cm tall. the student realises that, as his target will be moving, he must release the water bomb when his friend is a certain horizontal distance from the point of impact. if his friend is walking towards the overpass at 2m/s calculate the distance

h = ho  (Vo*t + 0.5g*t^2 = 1.71 m.
4.5  (0 + 4.9t^2 = 1.71
4.9t^2 = 1.71  4.5 = 2.79
t^2 = 0.5694
Tf = 0.755 = Fall time.
d = 2m/s * 0.755s = 1.51 m.
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