posted by Brun .
Nitric oxide (NO) can be removed from gas-fired power-plant emissions by reaction with methane as follows:
CH4(g) + 4NO(g) --> 2N2(g) + CO2(g) + 2H2O(g)
Complete the equation relating the rates for each of the following:
a) the rate of appearance of N2 to the rate of appearance of CO2
rate= ∆[N2]/∆t = ??/∆t
b)rate of appearance of CO2 to the rate of disappearance of NO
rate= ∆[CO2]/∆t = ??/∆t
c) rate of disappearance of CH4 to the rate of appearance of H2O
rate= -∆[CH4]/∆t = ??/∆t
a. I can't write a delta symbol. delta T will be dT.
rate = d[N2]/2*dT = d[CO2]/dT
b and c are done the same way except the disappearance is shown with a - sign.
rate = d[CO2]/dT = -d[NO]4*dT
they are saying that the d[CO2] for the d[CO2]/dT is wrong but I'm not sure why.