# Physics

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A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 575 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope to the left and to the right of the mountain climber.

• Physics -

ΣFx=0 0= T1•sin α-T2•sin β
0= T1•sin α-T2•sin β
ΣFy=0
m•g=T1•cos α+T2•cos β

T2= T1•sin α/sin β

m•g=T1•cos α+ T1•sin α•cos β /sin β =
=T1•cos α+ T1•sin α• /tanβ

T1=mg/(sinα/tanβ +cosα)=...
T2 =...

• Physics -

T1=970.08
T2=892.76

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