Logarithms

posted by .

Using the approximation log10^2=0.301, find:

log10^8

• Logarithms -

since 10^8 = 10^8,
log 10^8 = 8

giving the exponent makes finding the log easy, since a log is in fact an exponent

log 100 = 2
because 10^2 = 100

• Wrong, typo -

log 10^2 = IS NOT .301
but
log base 10 of 2 = .301
usually written log10(2)
I bet you want log base 10 of 8

log10 (2^3) = 3 log10(2) = 3(.301) = .903
which i bet is what your are looking for

• Logarithms -

Yes Damon that's what I meant. Thanks!

• Logarithms - my bad -

My bad. I didn't read the entire problem. I might even have caught the strange notation. Go with Damon.

• Logarithms -

It's fine. Thanks

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