precal
posted by ladybug .
for the given functions f & g find the specified value of the following functions and state the domain of each one.
f(x)=2+6/x; (g)x 6/x
a. (fg)(3)=
what is the domain of fg?
b. (f/g)(6)=
what si the domain of f/g?

a. (fg)(3)=(2+(6/3))  6/3 = 4  2=2.
Domain: All real values of X except 0.
0 > X > 0.
b. (F/G)(6)=((2+(6/6)) / (6/6) = 3/1=3.
Domain: All real values of x except o.
0 > X > 0.
Respond to this Question
Similar Questions

Math
for the given functions f and g find the following and state the domain of each result f(x)=3x+1/8x9; g(x)=5x/8x9 A) (f+g)(x)=? 
MATH
for the given functions f and g find the following and state the domain of each result f(x)=3x+1/8x9; g(x)=5x/8x9 A) (f+g)(x)=? 
calculus
for the given functions f&g, find the following and state the domain of each result. f(x)=5x+4/7x8; g(x)=2x/7x8 a.(f+g)(x)= ? 
calculus
for the given functions f&g, find the following and state the domain of each result. f(x)= 5x+4/7x8; g(x)= 2x/7x8 a. (f+g)(x)=? 
math
For the given functions f & g find the following and state the domain of each result. f(x)square root x;g(x)=5x1 a.(f*g)(x)= What is the domain of f*g? 
math
for the given functions f and g, find the specified value of the following functions and state the domain of each one. f(x)=2+3/x; g(x)=3/x a.(fg)(2)= b.(f/g)(3)= how do I do this? 
Algebra
Find the specified value of the following functions and state the domain of each one. f(x)=x11;g(x)=7x^2 (a) (f+g)(5)= 
For the given functions f and g
For the given functions f and g, find the following and state the domain of each result. f(x)=sqrtx;g(x)=5x9 (a) (f*g)(x)= What is the domain of f*g? 
College Algebra
For the given functions f and g, find the following and state the domain of each result. f(x)=√x;g(x)=7x2 (a)(f*g)(x)= What is the domain of f*g? 
Calculus
Find the sum and difference functions f + g and f – g for the functions given. f(x) = 2x + 6 and g(x) = 2x  6 f(x) = x^2  x and g(x) = 3x + 1 f(x) = 3x^3  4 and g(x) = x^2 + 3 State the domain and range for the sum and difference …