chemistry

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A certain weak base has a Kb of 9.00x10^-7. What concentration of this base will produce a pH of 10.30?

  • chemistry -

    pH = 10.3 = -log(H^+)
    (H^+) = 5.01E-11 and (OH^-) = 2E-4

    .........B + HOH ==> BH^+ + OH^-
    I........x............0.......0
    C........-y...........y.......y
    E........x-y..........y........y
    y = 2E-4

    Ka = 9.00E-7 = (BH^+)(OH^-)/(B)
    (BH^+) = (OH^-) = 2E-4
    (B) = x-2E-4. Solve for x-y

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