Precalc/Trig
posted by Patrick .
Find all values of x, 0<x<(pi/2) for which (1/( root 3))<cotx<(root 3)

0<x<(π/2) > x must be in quadrant I
1/√3 < cotx < √3
consider the "ends"
cotx = 1/√3 > tanx = √3 > x = π/3 or (60°)
cotx = √3 > tanx = 1/√3 > x = π/6 or (30°)
so π/6 < x < π/3