posted by D .
A room has dimensions 2.24 m (height) × 5.30 m × 6.55 m. A fly starting at one corner flies around, ending up at the diagonally opposite corner. (a) What is the magnitude of its displacement? (b) If the fly walks rather than flies, what is the length of the shortest path it can take? (Hint: This can be answered without calculus. The room is like a box. Unfold its walls to flatten them into a plane.)
d=√(5.30^2 + 6.55^2 + 2.24^2) = 8.718
Unfolding the room,
walk along the short wall to a point 1.0018m up the long wall, then up to the opposite corner
walk along the long wall to a point 1.238m up the short wall, then up to the opposite corner.
In either case, the distance traveled is 12.06m
walking the edges, the distance is 14.09m