precalculus
posted by ladybug
write the expression as a simple logarithm. express powers.
In(x/x5)+In(x+5/x)In(x^225)

Reiny
Assuming you meant:
In(x/(x5))+In((x+5)/x)In(x^225)
= lnx  ln(x5) + ln(x+5)  lnx  ( ln(x+5) + ln(x5) )
= lnx  ln(x5) + ln(x+5)  lnx  ln(x+5)  ln(x5)
= 2ln(x5)
or ln(x5)^2 or ln(x5)^2
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