phy

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force in the x-direction with magnitude Fx=18N-(0.530N/m)x is applied to a 5.50 box that is sitting on the horizontal, frictionless surface of a frozen lake. is the only horizontal force on the box.
what is the speed after 12m. starting from rest and x=0

  • phy -

    F=18-0.53•x
    a=F/m=(18-0.53•x)/5.5
    v=sqrt(2•a•x)=sqrt[(18-0.53•x)x/5.5]=
    = sqrt[(18 - 0.53•12) •12/5.5=5.04 m/s

  • phy -

    the first answer is wrong

  • phy -

    Integral of F(x) = .5mv^2
    18x-.5(.53)x^2=.5mv^2
    find v.

  • phy -

    8.04m/s

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