(a) how long it took King Kong to fall straight down from the top of a 210 m high building
s
(b) his velocity just before "landing"
4.86 sec
To calculate the time it took King Kong to fall straight down from the top of a 210 m high building and his velocity just before "landing," we can use the laws of physics and the equations of motion.
First, let's use the equation of motion for an object in free fall:
h = (1/2) * g * t^2
where:
h is the height of the building,
t is the time taken to fall, and
g is the acceleration due to gravity, which is approximately 9.8 m/s^2 on Earth.
For part (a) - time taken to fall:
We want to find 't' when the height is 'h.' Re-arranging the equation, we get:
t = sqrt(2h / g)
Substituting the given values, we have:
t = sqrt(2 * 210 / 9.8) ≈ 6.48 seconds
Therefore, it took King Kong approximately 6.48 seconds to fall straight down from the top of the 210 m high building.
For part (b) - velocity just before landing:
We know that the velocity, v, can be calculated using the equation:
v = g * t
Using the value of g from before and the value of t, we have:
v = 9.8 * 6.48 ≈ 63.5 m/s
Therefore, King Kong's velocity just before "landing" would be approximately 63.5 m/s.