posted by Audrey .
A 15.0 mL sample of 0.250 M H2SO4 is neutralized by 20.5 mL of KOH solution. What is the molarity of the KOH solution?
H2SO4 + 2KOH ==> 2H2O + K2SO4
mols H2SO4 = M x L = ?
Look at the equation to convert mols H2SO4 to mols KOH. mols KOH = 2x mols H2SO4
MKOH = mols KOH/L KOH. Solve for M KOH.
0.0250 mol H2S04 X (2 mol KOH/1 mol H2SO4)= 0.05 mol KOH
0.05 mol KOH/0.0150 L KOH= 3.33 M KOH