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A ferry is crossing a river. The ferry is headed
due north with a speed of 1.7 m/s relative to
the water and the river’s velocity is 2.4 m/s
to the east.
a) What is magnitude of the boat’s velocity
relative to Earth?
Answer in units of m/s
b) Find the direction in which the ferry is
moving (measured from due east, with counterclockwise positive).
Answer in units of

  • Physics -

    X = Hor. = 2.4 m/s.
    Y = Ver. = 1.7 m/s.

    a. Vb^2 = X^2 + Y^2.
    Vb^2 = 5.76 + 2.89 = 8.65
    Vb = 2.94 m/s. = Velocity of boat.

    b. tanA = Y/X = 1.7/2.4 = 0.70833
    A = 35.3o,CCW.

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