precalculus
posted by ladybug .
solve the following logarithmic equation. Be sure to reject any value of x that is not in thedomain of the orginal logarithmic expression. Give the exact answer.
log3(x+8)=4
The three actually drops down a little below the g. Can someone tell me how to do this?

since log3(x+8) = 4,
x+8 = 3^4
x+8 = 81
x = 73