posted by Donald .
When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky diver and, thus, slows him down. Suppose the weight of the sky diver is 914 N and the drag force has a magnitude of 1120 N. The mass of the sky diver is 93.3 kg. What are the magnitude and direction of his acceleration?
a= (F(fr)-W)/m = (1120-914)/93.3 = 2.2 m/s² (upwards)