Algebra
posted by Jessica .
If Samantha and Logan can do their paper route together in 45 minutes, how many hours would it take each of them to do it alone, given that Samantha is three times as fast as Logan?

Logans rate = 1/x
Samantha's rate = 3/x
combined rate = 1/x + 3/x = 4/x
1/(4/x) = 45
x/4 = 45
x = 180
time for Logan alone = 1/(1/180) = 180 minutes
time for Samantha alone = 1/(3/18) = 60 minutes
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