posted by Amanda .
a student conducts and experiment by reacting 39.6g CuSO4 with an excess of MgS. The reaction yields 9.5599g CuS. What is the percentage yield? MgS+CuSO4=CuS+MgSO4
mols CuSO4 = grams/molar mass = ?
Convert mols CuSO4 to mols MgS using the coefficients in the balanced equation.
Convert mols MgS to grams. g = mols x molar mass. This is the theoretical yield(TY). The actual yield (YD) in the problem is 9.5599 g.
Then %yield = (AY/TY)*100 = ?