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Pre-Calculus

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Radical Functions

Graph y=(x-3)(x+2) and y=√(x-3)(x+2). where are the x-intercepts of each function ?why?

for the first one, i know that whatever is inside the brackets is opposite, so the x intercepts would be at 3, and -2. but the whole radical thing is it the same process?

  • Pre-Calculus -

    graph one: x intercepts: 3 and -2
    graph two: x intercepts: 3 and -2

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