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A top fuel dragster can accelerate from 0-330mph in the time it takes to go 1000ft. assume that the acceleration is constant. what is the acceleration

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    x = 1/2 a * t^2
    v = a * t

    where x is distance, a is acceleration, t is time, and v is speed

    First you have to get the units to match. You probably want your answer of acceleration to be in ft/second^2, so convert 330 mph to ft/s

    330 miles/hour = 330 miles / 3600 s = 0.0916 miles / s = 0.0916 * 5280 ft / s
    = 484 ft / s

    Plug numbers into the equation:

    1000 = 1/2 a * t^2
    484 = a * t

    Use algebra to solve for a:

    t = 484 / a
    Plug equation for t into equation for x and you get:

    1000 = (.5 * (484)^2 ) / a

    solve for a

    a = (.5 * 484^2 )/ 1000

    a = 117 ft/s^2

    You can then convert this to other units if that's what the problem asks for (i.e., m/s^2, etc)

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