# Uni Physics

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Calculate the power required of a 1230 kg car as it climbs a 18° hill at a steady 92 km h-1. The total friction and air resistance is 700 N. Answer in kW, to the nearest whole number.

• Uni Physics -

speed = 92,000/3600 = 25.6 m/s

force = m g sin angle + 700

= 1230*9.81*.309 + 700 = 3729+700 = 4429 N

power = force * speed = 4429*25.6 = 113 KW

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