posted by damon .
can someone please explain the steps:
suppose that the grade point average,denoted by X,of a university student is Normally distributed with the mean 2.786 and standard deviation 0.375
A). a student is on the deans list if her GPA exceeds 3.746. What percent of the students are on the dean's list? P(X>3.746 GPA)
B). a student is on probation if his GPA falls below 1.946. what percent of the students are on probation?
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores. Multiply by 100 to convert to percent.