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Find a three digit number so that when the digita of the number Are added together the total is one fifth of the product of the digits

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    if the digits are a,b,c then

    5(a+b+c) = abc
    c = 5(a+b)/(ab-5)

    so, ab must be greater than 5,

    ab cannot be 6, since then a+b > 5
    if ab=7, then 5(8)/2 = 20 > 10
    if ab=8, then c = 5(6)/3 = 10 too big
    if ab=9, then c=5(6)/4 = not integer
    if ab=10, then c=5(7)/5 = 7

    257: 2+5+7 = 14 = 2*5*7/5

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