Find a three digit number so that when the digita of the number Are added together the total is one fifth of the product of the digits
if the digits are a,b,c then
5(a+b+c) = abc
c = 5(a+b)/(ab-5)
so, ab must be greater than 5,
ab cannot be 6, since then a+b > 5
if ab=7, then 5(8)/2 = 20 > 10
if ab=8, then c = 5(6)/3 = 10 too big
if ab=9, then c=5(6)/4 = not integer
if ab=10, then c=5(7)/5 = 7
257: 2+5+7 = 14 = 2*5*7/5
To find a three-digit number where the sum of its digits is equal to one-fifth of the product of its digits, we can use a simple step-by-step approach.
Let's consider the three-digit number as ABC, where A, B, and C represent the hundreds, tens, and units digits, respectively.
1. Start with the hundreds digit (A). Since we want the sum of the digits to be one-fifth of the product of the digits, we have A + B + C = (A * B * C) / 5.
2. Begin by trial and error. Start with values for A, B, and C and check if the equation holds true. Remember, A, B, and C must be nonzero digits.
3. For example, let's start with A = 1, B = 2, and C = 3.
Plugging these values into the equation, we get 1 + 2 + 3 = (1 * 2 * 3) / 5, which simplifies to 6 = 6/5. Since the equation is not true, we need to try a different combination.
4. Continue this process, trying different values for A, B, and C until we find a combination that satisfies the equation.
Using this method, you may find that there is no three-digit number that meets the given condition. However, if there is such a number, you will eventually find it by systematically testing different combinations of values for A, B, and C.