Calculusmath
posted by Anonymous .
Find an equation of the line that is tangent tothe graph of f and parallel tothe given line.
Function: 1/square root of x
Line: x+2y6=0

using slopeintercept, the given slope is 1/2
the slope of the tangent to the function is the 1st derivative
f(x) = 1 / sqrt(x) = x^(1/2)
f'(x) = (1/2) x^(3/2)
substitute to find x and then y at the point of tangency
use pointslope to write the equation of the new parallel line
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