CALCULUS HELP
posted by Herosugar .
Find the second derivative for the function 5x^3+60x^236x41
and solve the equation F(X)=0
i got to the second derivative but what do we do next to be able to get one of these answers..
F(x) = 5x3+60x2−36x−41
1. derivative of F(x)
with respect to x = 15x2+120x−36
2. derivative of F(x)
with respect to x = 30x+120
a. 4
b. 5
c. 0
d. 41
e. 36

Your derivatives are correct
As to solving f(x) = 0
5x^3+60x^236x41 = 0 is a tough one, since it does not factor
I used an apps to find
x = 1.11169
x = 12.5227
x = .589024