Math
posted by Gene .
The mystery number's tens digit is less than the ones digit.
The tens digit is less than the tenths digit.
The tens digit is even.
Its ones digit divided by its tens digit is 5.
The product of two of the digits is 6
It has two odd digits.
One of its digits is the sum of the other two digits.
One of its digits is seven

number: xx.x
ones/tens = 5, so ones=5,tens=1
15.x
how can tens be even? ones=5*tens, so if tens > 1, ones > 10, and isn't a single digit. Maybe the tenths digit is even?
I'd say 15.6
if one of the digits is 7, then I'd say
715.6 or 15.67 but the last rule says there are only 3 digits.
Where does the 7 fit in? can't say. If two of the digits multiply to give 6, then the number must contain 1,6 or 2,3.
Maybe the last rule is one of the digits is "even"?
I still stand by 15.6 but only if my suspected typos are true.
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