Exactly 11 kJ of energy was absorbed by 1 mol of Cl2(g) at 298 K. What i s thefinal temperature of the Cl2(g)? The heat capacity of Cl2(g) is 25.635J.K-1.mol-1
To find the final temperature of Cl2(g) after absorbing 11 kJ of energy, we can rearrange the formula for heat capacity (C) as follows:
Q = C * ΔT
Where:
Q is the heat absorbed in joules (11 kJ = 11,000 J),
C is the heat capacity of Cl2(g) in J.K-1.mol-1 (25.635 J.K-1.mol-1),
and ΔT is the change in temperature in kelvin (which we want to find).
Rearranging the formula, we have:
ΔT = Q / C
Substituting the given values into the formula:
ΔT = 11,000 J / (25.635 J.K-1.mol-1) = 428.91 K
Therefore, the final temperature of Cl2(g) is approximately 428.91 K.