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An elevator (cabin mass 600 kg) is designed for a maximum load of 2100 kg, and to reach a velocity of 3.1 m/s in 3 s. For this scenario, what is the tension the elevator rope has to withstand?

This is what I've tried and is incorrect.
2100kg + 600 kg= 2700kg (m)
(3.1/3)= 1.033m/s^2 (a)
2700 x 1.033= 2789.1N (F)
Please help.

  • Physics -

    you seem to have forgotten gravity

    add g to your acceleration number and you should be okay

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