posted by Lauren .
An elevator (cabin mass 600 kg) is designed for a maximum load of 2100 kg, and to reach a velocity of 3.1 m/s in 3 s. For this scenario, what is the tension the elevator rope has to withstand?
This is what I've tried and is incorrect.
2100kg + 600 kg= 2700kg (m)
(3.1/3)= 1.033m/s^2 (a)
2700 x 1.033= 2789.1N (F)
you seem to have forgotten gravity
add g to your acceleration number and you should be okay