Post a New Question

Physics

posted by .

A stone is dropped from the roof of a high building. A second stone is dropped 1.51 later. How far apart are the stones when the second one has reached a speed of 12.6 ?

  • Physics -

    Second Stone:
    d = (V^2-Vo^2)/2g.
    d = (158.76-0)/19.6 = 8.1 m.
    Tf = (V-Vo)/g = (12.6-0)/9.8 = 1.29 s. =
    Fall time.

    First Stone:
    Tf = 1.51 + 1.29 = 2.80 s.
    d = Vo*t + 0.5g*t^2.
    d = 0 + 4.9*2.8^2 = 38.3 m.

    D = 38.3 - 8.1 = 30.2 Meters apart.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question