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Physics

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a projectile is fired with an initial speed of 53 m/s. Find the angle of projection such that the maximum height of the projectile is equal to its horizontal range

  • Physics -

    range is v^2 sin(2θ)/g
    height is v^2 sin^2(θ)/2g

    so,

    sin(2θ) = sin^2(θ)/2
    2sinθcosθ = sin^2(θ)/2
    4cosθ = sinθ
    16cos^2(θ) = sin^2(θ) = 1 - cos^2(θ)
    17cos^2(θ) = 1
    cosθ = 1/√17

  • Physics -

    0.34 & 0.125

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