Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Calculus
is the lim (x tending to 0) of (sin(0))/0 = 1?
1 answer
yes
You can
ask a new question
or
answer this question
.
Related Questions
What is the following limit?
lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim
using the squeeze theorem, find the limit as x->0 of x*e^[8sin(1/x)]
what i did was: -1<=sin(1/x)<=1 -8<=8*sin(1/x)<=8
What is the following limit?
lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim
What is the following limit?
lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim
is the limit as x approaches 0 of sin3x over 3x equal to zero?
sorry-- basically this is my problem: lim [sin 3x / 4x) x-> 0
i keep on doing something wrong on this problem,i guess im forgetting to add or subtract some number.
use f'(x)=lim h-->0
Use the graph to estimate the limit:
lim x->0 sin(3x)/x When x is in degrees lim x->0 sin(3x)/x = ________ I thought the the
Can you please help me get the solution to this limit without using squeeze theorem and l'hopitals rule
lim x to 0 of x^3
5) Use the L’Hopital’s method to evaluate the following limits. In each case, indicate what type of limit it is ( 0/0,
yes! tnk u
ok? It's actually (x->0.) Find the limit of cot(x)-csc(x) as x approached 0? Lim [cot(x) - csc (x)] ..x->0 = Lim [(cos