Calculus
posted by Anne .
Determine the polar form of the complex number 3  2i. Express the angle theta in degrees, where 0 < theta < 360°, and round numerical entries in the answer to two decimal places.
326.31(cos 326.31° – isin 326.31°)
3.61(cos 326.31° – isin 326.31°)
326.31(cos 3.61° + isin 3.61°)
3.61(cos 326.31° + isin 326.31°)

r = √13, so it must be b or d
assuming that the angles are correct, the number is in IV, so (d) is the choice.
(since sin 326.31° < 0)
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