Post a New Question


posted by .

When 14 grams of a sample cools from 59C
to 27.8C it loses 20.9 Joules of heat. What is
the specific heat of the sample?

  • chemistry -

    q = mass x specific heat x (Tfinal-Tinitial)
    Substitute and solve for sp. h.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question