# calculus

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Differentiate the function.
y = (Square root x)(x − 10)

• calculus -

use the product rule on

y = (x^(1/2))(x-10)
dy/dx = x^(1/2) (1) + (1/2)x^(-1/2) (x-10)
= (1/2) x^(-1/2) ( 2x + x-10)
= (3x-10)/(2√x)

• calculus -

Thank you so much! I didn't think to use the product rule.

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