What mass of silver nitrate (AgNO3) is re-
quired to prepare 400 g of a 3.50% solution of
AgNO3?
1. 14 g
2. 0.00875 g
3. 114.28 g
4. 1400 g
percent what? w/w; w/v, v/v, etc.
I assume this is mass percent.
(g AgNO3/400 g soln)*100 = 3.50
Solve for g AgNO3.
Can you help me
To solve this problem, we need to find the mass of silver nitrate (AgNO3) required to prepare a 3.50% solution of AgNO3 with a total mass of 400 g.
First, let's understand what a 3.50% solution means. It means that 3.50 g of AgNO3 is dissolved in 100 g of the solution, by mass.
So, in a 400 g solution, the mass of AgNO3 can be calculated as follows:
Mass of AgNO3 = (3.50 g / 100 g) * 400 g
Mass of AgNO3 = 14 g
Therefore, the correct answer is 1. 14 g.