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three consecutive primes are summed. when the sum is squared, the result is 72,361. what is the largest of the three primes?

  • math -

    (sum of 3 consecutive primes )^2 = 72361
    sum of 3 consecutive primes = 269

    269/3 = 89

    so the middle prime must be around 89
    BUT 89 is a prime
    http://primes.utm.edu/lists/small/10000.txt

    the one before is 83 and the one after is 97
    So the largest of these primes is 97

    check:
    (83+89+97)^
    = 269^2
    = 72361 , YEAH!

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