The earth moves around the sun in a nearly circular orbit of radius 1.50 1011 m. During the three summer months (an elapsed time of 7.89 106 s), the earth moves one-fourth of the distance around the sun.
...and your question is...?
To find out how far the Earth moves during the three summer months, we can use the formula for calculating the distance traveled in a circular motion:
Distance = Circumference * (fraction of the circle)
The radius of the Earth's orbit is given as 1.50 * 10^11 m. The circumference of the orbit can be calculated using the formula:
Circumference = 2 * pi * radius
where pi is a mathematical constant approximately equal to 3.14.
Let's calculate the circumference of the Earth's orbit first:
Circumference = 2 * 3.14 * (1.50 * 10^11) m
Now, let's calculate the distance traveled during the three summer months, which is one-fourth of the distance around the sun:
Distance = Circumference * (1/4)
Now, we can substitute the values to calculate the distance:
Distance = (2 * 3.14 * (1.50 * 10^11) m) * (1/4)
Simplifying the equation:
Distance = (3.14 * 1.50 * 10^11 m) * (1/2)
Multiplying the numbers:
Distance = 4.71 * 10^11 m
Therefore, during the three summer months, the Earth moves a distance of approximately 4.71 * 10^11 meters around the Sun.