Math
posted by Mayank .
Q) Hasan buys two kinds of cloth materials for school uniforms, shirt material costs him Rs 50 per metre and trouser materia l costs him Rs 90 per meter. For every 2 meters of the trouser material he buys 3 meters of shirt material. He sells that material at12% and 10% profit respectively. His total sale is Rs36,660. How much trouser material did he buy?

profit on shirt material: 10% of 50 = 5.00/meter
profit on trouser: 12% of 90 = 10.8/meter
If he buys s meters of shirt, t meters of trouser, then
2s = 3t
1.10s + 1.12t = 36660
Hmmm. I expected to get integer values, but did not. Better check my math and the problem. 
hi in which standard r u , its just a simple sum , that means a very stupiod person is trying it out , but well i am the topper of the class i know this question well i am neha

hasan buys two kinds of cloth material for school uniforms,shirt material that cost him RS50 per meter and trouser material that costs him RS 90 per meter.for every 3 meters of shirt meateril he buys 2 meters of the trouser material.He sells the materials at 12% and 10% profit respectively .His total sale is RS 36,600. how mach trouser material did he bey?

Cost of 1m shirt material=Rs50
Cost of 1m trouser material=Rs90
Let Has an buys shirt material =3x
Hasan buys trouser material =2x
Cost of shirt material cloth=Rs50Ã—3x=150x
Cost of trouser material cloth =Rs90 Ã—2x=150x
S.P. of shirt material =C.P.Ã—(100+P%)Ã·100
=150xÃ—(100+12%)Ã·100
=150xÃ—112Ã·
=168x
S.P. of trouser material=C.P.Ã—(100+P%)Ã·100
=180xÃ—(100+10%)Ã·100
=180xÃ—110Ã·100
=198x
Total Sale =36600
=168x +198x=36600
=366x=36600
=Ã—=100
=Hasan buys trouser material =2x
=2Ã—100
=200metre 
Let measure of shirt material be 3x and measure of grouse be 2x.
Cost of 3xm shirt material= 3x×50=150x
Cost of 2xm grouse material= 2x×90=180×
Selling price of the shirt material=150x×112/100
Selling price of the trouser material=180x×110/100
Total selling price=150×112/100+180x×110/100=36600=366x=36600/360=100
Trouser material he buyed=2×100=200