calculus
posted by maura .
To find the equation of a line, we need the slope of the line and a point on the line.
Since we are requested to find the equation of the tangent line at the point (64, 8), we know that (64, 8) is a point on the line. So we just need to find its slope.
The slope of a tangent line to f(x) at x = a can be found using the formula
mtan = lim x→a f(x) − f(a)/x − a
In this situation, the function is
f(x) = a=

calculus  eh? 
Steve
so far, so good. What's the question?

calculus 
maura
its asking for f(x) and a
im just trying to figure out how i would go about doing this. thanks for answering me. 
calculus 
maura
i got a slope of 1/16 is that right?

calculus 
Steve
since I have no idea what f(x) is, I can't say. It never appears in the exercise posted.

calculus 
Steve
maybe if you showed your calculation of the slope I can figure out how you got it, and whether it's right.

calculus 
maura
well the question is from what im assuming is trying to find what f(x) is equal to. that's the last line of my question above. it also wants me to find what a is equal to. so to find slope i took the first derivative: y'= 1/ [2sqrt(x)] since x=64
makes this y'=1/(2*8) = 1/16 
calculus 
maura
this sentence doesnt look quite right it should look more like this
In this situation, the function is
f(x) = ? a= ?
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