geometry

posted by Jane

Algebra BD bisects <ABC. Solve for x and find m<ABC.

m<ABD = 4x - 16, m<CBD = 2x + 6

Please teach me how to work this.

1. Steve

since BD bisects <ABC, m<ABD = m<DBC

4x-16 = 2x+6
2x = 22
x = 11

m<ABC = m<ABD + m<DBC = 4*11-16 + 2*11+6 = 28+28 = 56

2. Jane

Steve, thank you so much. You explained it so I could understand it.

3. Steve

That's the plan. :-)

4. Arooj

in triangle ABC, BD bisects <ABC, <ABD = 4x + 6 and m<DBC = 5x -5. find the m<abc

5. Young thug

10007

6. Anonymous

bisects ∠ABC, m∠ABD = (6x − 8)°, and m∠CBD = (2x + 28)°. What is m∠ABC?

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