posted by Jane .
Algebra BD bisects <ABC. Solve for x and find m<ABC.
m<ABD = 4x - 16, m<CBD = 2x + 6
Please teach me how to work this.
since BD bisects <ABC, m<ABD = m<DBC
4x-16 = 2x+6
2x = 22
x = 11
m<ABC = m<ABD + m<DBC = 4*11-16 + 2*11+6 = 28+28 = 56
Steve, thank you so much. You explained it so I could understand it.
That's the plan. :-)
in triangle ABC, BD bisects <ABC, <ABD = 4x + 6 and m<DBC = 5x -5. find the m<abc