geometry
posted by Jane
Algebra BD bisects <ABC. Solve for x and find m<ABC.
m<ABD = 4x  16, m<CBD = 2x + 6
Please teach me how to work this.

Steve
since BD bisects <ABC, m<ABD = m<DBC
4x16 = 2x+6
2x = 22
x = 11
m<ABC = m<ABD + m<DBC = 4*1116 + 2*11+6 = 28+28 = 56 
Jane
Steve, thank you so much. You explained it so I could understand it.

Steve
That's the plan. :)

Arooj
in triangle ABC, BD bisects <ABC, <ABD = 4x + 6 and m<DBC = 5x 5. find the m<abc

Young thug
10007

Anonymous
bisects ∠ABC, m∠ABD = (6x − 8)°, and m∠CBD = (2x + 28)°. What is m∠ABC?
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