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chemistry

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We have an aqueous solution that contains
47% (by mass) of a hypothetical solute Z. The
formula weight of the solute Z is 209 g/mol.
The density of the solution is observed to be
1.3 g/mL. What is the molarity of Z in this
solution?
Answer in units of mol/L

  • chemistry -

    1.3 g/mL x 1000 = ? g = mass of 1L soln.
    ?g x 0.47 = ? g Z in the L.
    mols Z = ?g Z/209 = ? mols in that L; therefore that is the M in moles/L.

  • chemistry -

    Thank you for your help.

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