posted by .

This is the same equation as before just with different numbers.

y=yo + (vo sin Q) t - 1/2gt^2

This time the numbers are:

0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2

4.9t^2 - 1.5105 - 1.005 = 0
This is the part where I am stuck. Did I do this correctly? sin 30 = 0.50 X 3.021 = 1.5105 and then I would subtract this from 1.005

so then it would be 1.5105 - 1.005 = 0.5055 / 4.9 and square root it.

You are making a similar mistake to yesterday's error.
Yesterday you just magically tagged a t at the end of the first term, now you are dropping the t from the second term

0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2
looks ok, assuming your replacement values were correct
then
0 = 1.005 + 1.5105t - 4.9t^2 , since sin 30° = 1/2

4.9t^2 - 1.5105t - 1.005 = 0 , look at yours

you will have to use the quadratic formula

t = (1.5105 ± √(1.5105^2 - 4(4.9)(-1.005) )/9.8
= .... you do the button-pushing

I think you dropped a t:

4.9t^2 - 1.5105t - 1.005 = 0

the coefficients are correct, so now you just have to solve the quadratic equation.

t = 0.154 ± √0.229

## Similar Questions

1. ### trig integration

i'm having trouble evaluating the integral at pi/2 and 0. i know: s (at pi/2 and 0) sin^2 (2x)dx= s 1/2[1-cos(2x)]dx= s 1/2(x-sin(4x))dx= (x/2)- 1/8[sin (4x)] i don't understand how you get pi/4 You made a few mistakes, check again. …
2. ### math

Eliminate the parameter (What does that mean?
3. ### TRIG!

Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 …
4. ### pre calc trig check my work please

sin x + cos x -------------- = ? sin x sin x cos x ----- + ----- = sin x sin x cos x/sin x = cot x this is what i got, the problem is we have a match the expression to the equation work sheet and this is not one of the answers. need

using the equation y=yo + (vo sin Q) t - 1/2gt^2 I have to find t. The values for y, yo and vo were given to me. So I set the equation up like this: 0=1.005 + (3.107 sin 0) t - 1/2(9.8)(t^2 The sin of 0 is 0 times 3.107 is 0. So 0 …

Using the equation y=yo + (vo sin Q) t - 1/2gt^2 I have to find t. The values for y, yo and vo were given to me. So I set the equation up like this: 0=1.005 + (3.107 sin 0) t - 1/2(9.8)(t^2 The sin of 0 is 0 times 3.107 is 0. So 0 …
7. ### Math

This is the same equation as before just with different numbers. y=yo + (vo sin Q) t - 1/2gt^2 This time the numbers are: 0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2 4.9t^2 - 1.5105 - 1.005 = 0 This is the part where I am stuck. Did …