Physics

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A stone is thrown straight upward with a speed of 12 m/s from the edge of a 70 m high cliff. How long is the stone in the air? What is the speed just before it hits the ground? What is the total distance the stone traveled?

  • Physics -

    (a) Height of object from cliff base
    = H = 70 +12 t - (g/2) t^2
    Set H = 0 and g = 9.8 m/s^2, and solve for t. Take the positive rooot.
    (b) Vfinal^2 = Vinitial^2 + 2*g*70
    = (144 +1372) m^2/s^2
    Vfinal = 38.9 m/s
    (c) (Up distance) + (Down distance)
    = 2*(Up distance) + 70 m
    = 2*Vo^2/(2*g)+70
    = (Vo^2/g) + 70

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