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A body moving with an initial velocity of 10m/s has a uniform acceleration of 2m/s.Find distance travelled in the 8th second of its motion?

  • Science -

    s(t) = 10t + t^2
    s(7) = 70+49 = 119
    s(8) = 80 + 64 = 144

    distance in 8th second = 144-119 = 25m

    or, s = ∫[7,8] 10+2t dt

  • Science -

    26m/s

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