MATH
posted by SHANA .
WHAT IS THE SUM OF ALL THE DISTINCT, POSITIVE PRIME FACTORS OF 1260

MATH 
Jason
You have to break 1260 down into it's number tree. Start by dividing the number by 2 until you can't do it evenly, then divide by 3, and so on until no more divisions can be made:
1260/2 = 630
So we have one prime factor, 2 and are left with 630:
630/2 = 315
Now we have two prime factors, 2 and 2. We are left with 315:
315/3 = 105
Now we have three prime factors  2,2,3. We are left with 105:
105/3 = 35
Now we have four prime factors  2,2,3,3. We are left with 35:
35/5 = 7
Now we have SIX prime factors  2,2,3,3,5,7. Thus the sum of all the distinct, positive prime factors of 1260 are:
2+2+3+3+5+7 = 22
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What is the sum of the prime factors of 1260?