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A speed skater moving across frictionless ice at 9.0 hits a 6.0 -wide patch of rough ice. She slows steadily, then continues on at 6.1 m/s. What is her acceleration on the rough ice?

  • physics -

    a = ∆(v^2)/2s = (6.1^2 - 9^2)/12 = -3.65

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